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Lời giải:
\(=\frac{5.2^2.2^{30}.3^{20}-2^2.3^{21}.2^{30}}{5.2.2^{20}.5^{10}.2^{20}.3^{20}-2^{31}.3^{21}}=\frac{5.2^{32}.3^{20}-2^{32}.3^{21}}{5^{11}.2^{41}.3^{20}-2^{31}.3^{21}}\\
=\frac{2^{32}.3^{20}(5-3)}{2^{31}.3^{20}(5^{11}.2^{10}-3)}\\
=\frac{2^{33}.3^{20}}{2^{31}.3^{20}(5^{11}.2^{10}-3)}=\frac{4}{5^{11}.2^{10}-3}\)
A = \(\dfrac{21^2.14.125}{35^5.6}\)
= \(\dfrac{\left(3.7\right)^2.\left(2.7\right).5^3}{\left(5.7\right)^5.\left(2.3\right)}\)
= \(\dfrac{3^2.7^2.2.7.5^3}{5^5.7^5.2.3}\)
= \(\dfrac{3^2.7^3.2.5^3}{5^5.7^5.2.3}\)
= \(\dfrac{3}{5^2.7^2}\)
= \(\dfrac{3}{35^2}\)
@Pham Thi Thu Trang
B = \(\dfrac{2^{10}.13+2^{10}.65}{2^8.104}\)
= \(\dfrac{2^{10}\left(13+65\right)}{2^8.104}\)
= \(\dfrac{2.78}{104}\)
= \(\dfrac{3}{2}\)
@Pham Thi Thu Trang
Câu b:
B = (3\(^{10}\).11 + 3\(^{10}\).5) : (3\(^9\).2\(^4\))
B = 3\(^{10}\).(11 + 5): (3\(^9\).2\(^4\))
B = 3\(^{10}\).16:(3\(^9\).2\(^4\))
B = (3\(^{10}\) : 3\(^9\)).(16 : 2\(^4\))
B = 3.1
B = 3
Câu c:
C = (2\(^{10}\).13 + 2\(^{10}\).65) : (2\(^8\).104)
C = 2\(^{10}\).(13 + 65):(2\(^8\).104)
C = 2\(^{10}\).78 : (2\(^8\).104)
C = (2\(^{10}\) : 2\(^8\)).(78 : 104)
C = 2\(^2\).\(\frac34\)
C = 3