Câu hỏi của nhím

Question

<p dir="ltr"><img src="https://cdn4.olm.vn/upload/2026/0728/1785205881032_kj7p6y.png" alt="image.png" /><span style="white-space:pre-wrap;"> 🙃</span><img src="https://cdn4.olm.vn/upload/2026/0728/1785...

Huỳnh Gia Bảo · Accepted Answer

9.

a) $7^3<7^5$

b) $9^{12}<11^{12}$

c) $1^{14}=1^{13}$

d) $46^7<47^8$

10.

a) Ta có:

$13^2=169$

$6^3=216$

Vì 169 < 216 nên $13^2<6^3$

b) Ta có:

$6^2+8^2=36+64=100$

$\left(6+8\right)^2=14^2=196$

Vì 100 < 196 nên $6^2+8^2<\left(6+8\right)^2$

c) Ta có:

$13^2-9^2=169-81=88$

$\left(13-9\right)^2=4^2=16$

Vì 88 > 16 nên $13^2-9^2>\left(13-9\right)^2$

d) Ta có:

$6^3-4^3=216-64=152$

$\left(6-4\right)^3=2^3=8$

Vì 152 > 8 nên $6^3-4^3>\left(6-4\right)^3$

Câu trả lời:

9.

a) $7^3<7^5$

b) $9^{12}<11^{12}$

c) $1^{14}=1^{13}$

d) $46^7<47^8$

10.

a) Ta có:

$13^2=169$

$6^3=216$

Vì 169 < 216 nên $13^2<6^3$

b) Ta có:

$6^2+8^2=36+64=100$

$\left(6+8\right)^2=14^2=196$

Vì 100 < 196 nên $6^2+8^2<\left(6+8\right)^2$

c) Ta có:

$13^2-9^2=169-81=88$

$\left(13-9\right)^2=4^2=16$

Vì 88 > 16 nên $13^2-9^2>\left(13-9\right)^2$

d) Ta có:

$6^3-4^3=216-64=152$

$\left(6-4\right)^3=2^3=8$

Vì 152 > 8 nên $6^3-4^3>\left(6-4\right)^3$

Nguyễn Lê Phước Thịnh · Answer

Bài 7:

a: $2+3^2+4^2+13^2$

$=2+9+16+169$

$=11+185=196=14^2$

b: $1^3+2^3+3^3+4^3+5^3+6^3$

=1+8+27+64+125+216

=441=$21^2$

c: $5^3+6^2+8^2$

=125+36+64

=125+100

=225

=$15^2$

d: $1^3+2^3+3^3+4^3+5^3$

=1+8+27+64+125

=225

$=15^2$

Bài 8:

$Q=2^3+4^3+\cdots+20^3$

$=2^3\left(1^3+2^3+\cdots+10^3\right)$

$=2^3\cdot3025=3025\cdot8=24200$

Bài 6:

a: $A=2^2\cdot5^2-3^2-10$

=100-9-10

=81

$=9^2$

b: $B=3\left(5^2-4^2\right)$

$=3\cdot\left(25-16\right)=3\cdot9=27=3^3$

c: $C=5\cdot4^3+2^4\cdot5$

$=5\cdot\left(64+16\right)$

$=5\cdot80=400=20^2$

d: $D=5^3+6^3+7^3+79\cdot2^2$

=125+216+343+316

=1000

$=10^3$

Câu trả lời:

Bài 7:

a: $2+3^2+4^2+13^2$

$=2+9+16+169$

$=11+185=196=14^2$

b: $1^3+2^3+3^3+4^3+5^3+6^3$

=1+8+27+64+125+216

=441=$21^2$

c: $5^3+6^2+8^2$

=125+36+64

=125+100

=225

=$15^2$

d: $1^3+2^3+3^3+4^3+5^3$

=1+8+27+64+125

=225

$=15^2$

Bài 8:

$Q=2^3+4^3+\cdots+20^3$

$=2^3\left(1^3+2^3+\cdots+10^3\right)$

$=2^3\cdot3025=3025\cdot8=24200$

Bài 6:

a: $A=2^2\cdot5^2-3^2-10$

=100-9-10

=81

$=9^2$

b: $B=3\left(5^2-4^2\right)$

$=3\cdot\left(25-16\right)=3\cdot9=27=3^3$

c: $C=5\cdot4^3+2^4\cdot5$

$=5\cdot\left(64+16\right)$

$=5\cdot80=400=20^2$

d: $D=5^3+6^3+7^3+79\cdot2^2$

=125+216+343+316

=1000

$=10^3$

phong nguyen · Answer

5. a) A= $\left(2^9\cdot3+2^9\cdot5\right):2^{12}$

=$2^9\left(3+5\right):2^{12}$

= $2^9\cdot2^3:2^{12}$

= $1$

b). <=> $B=\left\lbrack2^9\left(16+34\right)\right\rbrack:2^{10}$

= $\left(2^9\cdot50\right):2^{10}$

= $\left(2^9\cdot50\right):\left(2^9\cdot2\right)$

= 25

c)$\left(3^4\cdot57-9^2\cdot21\right):3^5$

= $\left\lbrack3^4\left(57-21\right)\right\rbrack:3^5$

= $\left(3^4\cdot36\right):\left(3^4\cdot3\right)$

= 12

d) $D=\left(3^8\cdot17+3^9\cdot5\right):3^7\cdot2^5$

= $3^8\left(17+15\right):\left(3^7\cdot32\right)$

= $\left(3^8\cdot32\right):\left(3^7\cdot32\right)$

= 3

e) nhận thấy $\left(65\cdot111-13\cdot15\cdot37\right)$

= $\left(65\cdot111-13\cdot5\cdot3\cdot37\right)$

= $\left(65\cdot111-65\cdot111\right)=0$

bài 6:

a) $A=2^2\cdot5^2-3^2-10$

= $4\cdot25-9-10$

= $81=9^2$

b) $B=3\cdot\left(5^2-4^2\right)$

$B=3\cdot9=27=3^3$

c) $C=5\cdot4^3+2^4\cdot5$

= $5\left(4^3+2^4\right)$

= $5\cdot80$

= $400=20^2$

d) $D=5^3+6^3+7^3+79\cdot2^2$

= $125+216+343+79\cdot4$

= $1000=10^3$

bài 7:

a) $2+3^2+4^3+13^2$

= $2+9+16+169$

= $196=14^2$

b) $1^3+2^3+3^3+4^3+5^3+6^3$

= $1+8+27+64+125+216$

= $441=21^2$

c) $5^3+6^2+8^2$

= $125+36+64$

= $225=15^2$

d) $1^3+2^3+3^3+4^3+5^3$

ta có công thức $1^3+\cdots+n^3=\left(1+\cdots+n\right)^2$

= $\left(1+2+3+4+5\right)^2=15^2$

bài 8:

<=> Q=$8\left(1^3+2^3+..+10^3\right)$

=> Q= $8\cdot3025=24200$

bài 9:

a) $7^3<7^5$

b) $9^{12}<11^{12}$

c) $1^{14}=1^{13}$

d) $46^7<47^8$

bài 10:

a) ta có $13^2=169<6^3=216$

b) ta có: $6^2+8^2=100<\left(6+8\right)^2=196$

c) ta có: $13^2-9^2=88>\left(13-9\right)^2=16$

d) ta có: $6^3-4^3=152>\left(6-4\right)^3=8$

Câu trả lời:

5. a) A= $\left(2^9\cdot3+2^9\cdot5\right):2^{12}$

=$2^9\left(3+5\right):2^{12}$

= $2^9\cdot2^3:2^{12}$

= $1$

b). <=> $B=\left\lbrack2^9\left(16+34\right)\right\rbrack:2^{10}$

= $\left(2^9\cdot50\right):2^{10}$

= $\left(2^9\cdot50\right):\left(2^9\cdot2\right)$

= 25

c)$\left(3^4\cdot57-9^2\cdot21\right):3^5$

= $\left\lbrack3^4\left(57-21\right)\right\rbrack:3^5$

= $\left(3^4\cdot36\right):\left(3^4\cdot3\right)$

= 12

d) $D=\left(3^8\cdot17+3^9\cdot5\right):3^7\cdot2^5$

= $3^8\left(17+15\right):\left(3^7\cdot32\right)$

= $\left(3^8\cdot32\right):\left(3^7\cdot32\right)$

= 3

e) nhận thấy $\left(65\cdot111-13\cdot15\cdot37\right)$

= $\left(65\cdot111-13\cdot5\cdot3\cdot37\right)$

= $\left(65\cdot111-65\cdot111\right)=0$

bài 6:

a) $A=2^2\cdot5^2-3^2-10$

= $4\cdot25-9-10$

= $81=9^2$

b) $B=3\cdot\left(5^2-4^2\right)$

$B=3\cdot9=27=3^3$

c) $C=5\cdot4^3+2^4\cdot5$

= $5\left(4^3+2^4\right)$

= $5\cdot80$

= $400=20^2$

d) $D=5^3+6^3+7^3+79\cdot2^2$

= $125+216+343+79\cdot4$

= $1000=10^3$

bài 7:

a) $2+3^2+4^3+13^2$

= $2+9+16+169$

= $196=14^2$

b) $1^3+2^3+3^3+4^3+5^3+6^3$

= $1+8+27+64+125+216$

= $441=21^2$

c) $5^3+6^2+8^2$

= $125+36+64$

= $225=15^2$

d) $1^3+2^3+3^3+4^3+5^3$

ta có công thức $1^3+\cdots+n^3=\left(1+\cdots+n\right)^2$

= $\left(1+2+3+4+5\right)^2=15^2$

bài 8:

<=> Q=$8\left(1^3+2^3+..+10^3\right)$

=> Q= $8\cdot3025=24200$

bài 9:

a) $7^3<7^5$

b) $9^{12}<11^{12}$

c) $1^{14}=1^{13}$

d) $46^7<47^8$

bài 10:

a) ta có $13^2=169<6^3=216$

b) ta có: $6^2+8^2=100<\left(6+8\right)^2=196$

c) ta có: $13^2-9^2=88>\left(13-9\right)^2=16$

d) ta có: $6^3-4^3=152>\left(6-4\right)^3=8$

Phân số	Đọc	Tử Số	Mẫu số
\(\dfrac{5}{7}\)	Năm phần bẩy	5	7
\(\dfrac{-6}{11}\)	âm sáu phần mười một	-6	11
\(\dfrac{-2}{13}\)	âm hai phần ba	-2	13
\(\dfrac{9}{-11}\)	chín phần âm mười một	9	-11

Chúng tôi đề xuất

Tài nguyên

Ứng dụng mobile

Bảng xếp hạng

Phần quà đặc biệt từ OLM

Hè này, gói VIP OLM có gì cho bạn?

Các khóa học có thể bạn quan tâm

Yêu cầu VIP